## Tuesday, October 31, 2006

### My Game

My game is called "Jeffopoly." This is how you play, you first spin the spinner. If the pointer lands on blue you move 3 spaces forward and if you land on white you mave 2 spaces forword. There are spaces that you can "miss a turn," "move spaces," or move back spaces." First person to make it back to the finish wins. This is a fair game because the is a 50/50 chance of getting a blue or whte and either way you can move spaces.

J.A.A

## Monday, October 30, 2006

### Scribe List

The Scribe List
This is the Scribe list. If a name highlighted in blue the student has already done a scribe for this cycle. You will be expected to scribe once every 30 classes. This link explains the job of a Scribe. Please choose a name from this list as the next person who will be the next scribe.

This is the second round of the scribe list. If you have an * beside your name you did not do a scribe during the first round. You may do a scribe any day you want to catch up. You still will be responsible to do a scribe if you are chosen during round 2.

Part of being a scribe is leaving comments. You will be expected to leave comments behind at the sites provided in the Blogs that scribe link in your side bar.

 MichaelJeffMatthew*StephanieJames CMelissa(2?)MarygraceLeslieAshley* Jessica*James G*Brandon*Kim I*MaryDakotaLisaRoberto*AngelicEarl JeysonArdiaJustinMelvinSarika*Monique*Thyrza MayKimVTeaganKrystina

## Sunday, October 22, 2006

### Math Pg E-50 Question #1

1 . Suppose you roll a regular 6-faced die .

How many equally likely outcomes are there ?
There are 6 outcomes (1,2,3,4,5,6)

If you roll the die once, what is the probability of rolling a 3 ?
The probability of rolling a 3 would be 1/6 or 16.67%

If you roll the die 60 times, about how many times would you expect to get a 1 ?
i would expect to get a one 10/60 =1/6 or 16.67%

If you roll the die 300 times , about how many times would you expect to get a 5?
i would expect to get a 5 50/300= 1/6 or 16.67%

haha yeah i knoe the dice really ugly =P

My Question

if you roll an 8-faced die 600 times how many times would you expect to get the number 7 ? explain you answer in a fraction and a percent.

i would expect to get then number 7 75/600 =1/8 or 12.5%

## Wednesday, October 18, 2006

### solving # 4

Question of problem 4.

1. If you flip a coin 150 times, about how many times would you expect to get heads?

If you divide 150 into 2 gives you 75/150

2. The letters a, e, i, o, u, and y are vowels. If one letter of the alphabet is chosen at random, what is the probability it is a vowel?

The answer would be 7/26, how, add all the vowels together and, how many the probability is 7/26

3. If you randomly pick a date in April, how many equally likely outcomes are there?

The answer would be 30, because there are 30 days in April.

4. A magician asks you to pick a card, any card, from a standard deck of 52 cards. What is the probability of picking an ace?

The probability of picking a ace would be 4/52 and you can simplify to 2/26and you can do it one more time to be 1/13. So the answer would be 1/13

This is my question if you have 10 pens, 14 pencils, 16 erasers, and 9 rulers. How many outcomes can you have?

### Probability Homework !

E-50 #4

If you flip a coin 150 times, about how many times would you expect to get heads?

The theoretecial probability of getting a head if you flip a coin 150 times is 50%.When you look at a coin how many sides are there or how many total possible outcome are there?

LOOK:

Two right? A head and a tail! For example when you flip a coin once, you have a 50% chance it is a head and a 50% chance it is a tail. It is the same when you flip it 150 times, you still have a 50% chance of getting a head and 50% chance on getting a tail! Then divide 150 by 2 what is the answer? 75 is the answer!

So to get the percent, you divide 75(number of heads) by 150(total possible outcome) and then multiply the quotient by 100 and that gives you 50%.

Fraction: Simplify
THE NUMBER OF HEADS -------> 75 or 1

TOTAL POSSIBLE OUTCOME ---->150 or 2 or 75 in 150

__________________________________________________________
The letters a, e, i, o, u, and y are vowels. If one letter of the alphabet is chosen at random, what is the probability it is a vowel.

The theoretical probability of choosing a vowel if you pick a letter of the alphabet randomlu is 23.077%. To start of how many letters are in the alphabet or how many total possible outcome are there?

LOOK:
As you can see above, there are 26 letters in the alphabet and in this case there are 6 vowels which are a , e, i, o, u, and y. So the probability of choosing a vowel is 6/26.

So to get the percent, you divide 6(number of vowels) by 26 (total possible outcome) and then multiply the quotient by 100 and that gives you 23.077%

FRACTION:
Simplify
THE NUMBER OF HEADS ---------> 6 or 3
TOTAL POSSIBLE OUTCOME ---->26 or 13 or 6 in 26

_____________________________________________
If you randomly pick a date in April, how many equally likely outcomes are there?

I only have on question for you! How many days are there in April?

LOOK:

There are 30 days right? Yes ! Maybe you're wondering why I asked you how many days are there in April. It is because the total amount of days in April is the total possible outcome so the answer is 30 outcomes.

____________________________________________________

A magician asks you to pick a card, any card, from a standard deck of 52 cards. What is the probability of picking an ace?

The theoretical probability of choosing an ace from a standard deck of 52 cards is 7.692%. How many cards are in one group(e.g. spades, hearts, diamond, flower)?
LOOK:

There are 13 cards in each groupd 13 in hearts, 13 in spades, 13 in diamond and 13 in flower. In each groupd there are only 1 Ace and there are 4 grooups so you multiply 4 by 1 it equals to 4 so the answer is 4 in 52.

So to get the percent, you divide 4(number of Ace) by 52(total possible outcome) and then multiply the quotient by 100 and that gives you 7.692%.

FRACTION:
Simplify
THE NUMBER OF HEADS ---------> 4 or 1
TOTAL POSSIBLE OUTCOME ---->52 or 13
or 4 in 52

My question:

A magician asks you to pick a card, any card, from a standard deck of 52 cards. What is the probability of picking a king, a queen and an ace?

Others might make some errors such as when changing fractions to percent they might accidentally press x 10 in their calculator instead of x 100, they might miscount the total possible outcome, they might forget to simplify and more. You could prevent that especially on tests by checking your answer twice.

FEEL FREE TO COMMENT AND IF YOU FIND A MISTAKE KINDLY COMMENT ON THIS POST . THANK YOU!

Probability Game

Krystina Yso, KIm Thanh Vo and I invented a game called probability game. To play this game you need bears and an 8 sided dice. The rule is that only a maximum of 4 people can play. The youngest get to choose a bear first and the oldest get to roll the dice first. Each player can move their bear one step forward if they roll a 1,2,3 or 4 and if they roll a 5,6,7 or 8 they have to go back one step but there are some obstacles so be careful.

When you land on an apple, you get to roll again.
When you land on a bus, you get to go ahead 3 steps.
When you land on a stop sign, you miss a turn.
When you land on an occupied square you have to go a step behind them.
When you land on a white space, you have to pick a card and follow what it says.

It would be fair because everyone gets a turn, everyone gets to choose a bear and everyone has a 50% chance of moving a step forward and a 50% chance of moving a step backward. It would be fun because 1st prize gets 3 chocolates, 2nd prize gets 2 chocolate, 3rd prize gets 1 chocolate.

Here's what the game looks like:

### Math Question

1. Suppose you roll a 6 faced die.

A. How many equally outcomes are there?

E. If you roll the die once,what is the probability of rolling a 3?

H.If you roll the die 60 times about how many times would you expect to get a 1?

you might roll it 6 times.

My question: Someone gave you 5 eminems there were 2 green, 2 yellow,and 1 red. What is the probability of eating a green one?

## Monday, October 16, 2006

### mMm dela cruzzz's math homework...

E-49
Marygrace Dela Cruz . . .

19. The probability of winning a raffle if 500 tickets are sold and you buy 5 of them is 5/500 or 1/100. you would only have a 1 percent chance that you would get a winning raffle.

20. The probability that a girl will be chosen from random of 25 students is 15/25.

Every random pick out of 25, 15 times it will be a girl.

21. The probability that a letter is chosen at random in the word MATHEMATICS is 8/26 or 4/13.
Because there are two Ms, two As, and two Ts, there are 8 DIFFERENT letters.
My own question:
What is the probability that a letter chosen at random is in the word . . .
SUPER­CALI­FRAGI­LISTIC­EXPI­ALI­DOCIOUS???
Well scince there are ...
- 3 Ss - 3 Ls
- 2 Us - 7 Is
- 2 Ps - 1 F
- 2 Es - 1 G
- 2 Rs - 1 T
- 3 Cs - 1 X
- 3 As - 1 D
- 2 Os
... and only 26 letters in the alphabet,
the probability of a letter being chosen
at random is this word is 15/26.
There are only 15 DIFFERENT letters.

### Math Questions

1. 1/5 (red) This is 1/5 because there is only 1 chance out of 5 of getting red
2.1/5 (green) This is 1/5 because there is only 1 chance out of 5 of getting green

3.2/5 (blue or white) This is 2/5 because there is only 2 chances of 5 of getting blue or white
4. 4/5 (not yellow) This is 4/5 because there is only 4 out of 5 chances of not getting yellow
5.4/5 (not red) This is 4/5 because there is only 4 out of 5 chances of not getting red
6. 3/5 (blue, white and yellow) This is 3/5 because there is only 3 out of 5 chances of getting blue white or yellow
Question I created:
Find the Probability of getting a white??

### e-50 #2

Angelic M.
October 16,2006
8-41

2. A spinner is shown below for which outcome is NOT equally likely.

(E) If you spin the spinner once, what is the probability that it'll stop on A?
A takes up the same amount of romm that b and c do together. If you divide A in half, there would be 4 parts. Then there are 2 a's so, 2/4 or 1/2.
(A) If you spin the spinner once, what is the probability that it'll stop on B?
Again, A stands for 2 parts, so there are 4 parts all together. B takes up one of the 4 spots so, 1/4.
(T) If you spin the spinner 50 times, about how many times would you expect it to stop on A?
A takes up half of the room. Half of 50 equals 25. 25 is the answer.
(Y) If you spin 80 times, about how many times would you expect to stop on C?
C takes up a quarter of the room. A quarter is the same thing a as a fourth. 80 divided by 4 equals 20. 20 is the answer.
(MY QUESTION) If you spin the spinner 240, how many times would it supposedly stop on B?
240 divided by 4 equals 60 (24 divided by 4 equals six, add a zero at the end, voila!). Again B takes up a fourth of the space, and so forth, the answer is 60!

1)

2) (1) 1/5 (2)1/5 (3) 1/5 (4) 4/5 (5) 4/5 (6) 1/5

3) Find the probability of spinning on white.

Leslie 8-41 Oct. 16, 2006

### Math Questions & Answers Page E-50 Part VI (# 2)

A spinner is shown at the right for which each outcome is NOT equally likely.

If you spin the spinner once, what is the probablity that it will stop on A?

The probablity of the spinner landing on A after one spin would be Pa=2/4, or simplified to Pa=1/2, because A takes up half or two quarters of the spinner. (A/AllOtherAreas)

If you spin the spinner once, what is the probablity that it will stop on B?

The probablity of the spinner landing on B after one spin would be Pb=1/4, because B takes up 1 quarter of the spinner. (B/AllOtherAreas)

If you spin the spinner 50 times, about how many times would you expect it to land on A?

You would expect the spinner to stop on A about 25 times, because the probablity of getting A is 1/2. And 25 is half of 50.

If you spin the spinner 80 times, about how many times would you expect it to land on C?

You would expect the spinner to stop on C about 20 times, because the probablity of getting C is 1/4. And 20 is one quarter of 80.

--{*Create-A-Question*}--

Pretend B took up about 40% (2/5) of the spinner, and C took only 10% (1/10) of the spinner.

Then, if you spinned the spinner 20 times, how many times would it land on B?

Or on C?

Or A?

-apuya

### Math Questions and Answers E-49 16-21

16.What is the probablility of guessing the correct answer to a multiple choice question if there are 5 choices?

17.What is the probability of guessing the correct answer to a true-false question?

18.What is the probability that your birthday will fall on Saturday or Sunday?
-2/7 = Saturday,Sunday/total number of days in a week.

19.What is the probability of winning a raffle if 500 tickets are sold and you buy 5 of them?
-5/500=1/100 = # of "my" raffle tickets(ya thats right,MINE!)/#of tickets sold.

20.A class of 25 students has 15 girls and 10 boys. If one student is chosen at random, what is the probability it is a girl?
-15/25 = # of girls/# of total students.

21.There are 26 letters in the alphabet(wow i didn't know thatXD). What is the probability that a letter chosen at random is in the word MATHEMATICS?
-8/26 = there is 11 letters in mathematics but there are only 8 different letters.

Question. At the Grey Cup game the seats went all around the stadium and there are 100,000 seats in total. There are also only three rows. 50,000 in the top row, 25,000 in the middle row and 25,000 seats in the bottom row. If i buy a ticket for each row what is the probability i will get all middle seats in each row? This ones a brain teaser!

### Math Questions III: p. E-49

16.
What is the probablility of guessing the correct answer to a multiple choice question if there are 5 choices?
-P 1/5

17.
What is the probability of guessing the correct answer to a true-false question?
-P 1/2

18.
What is the probability that your birthday will fall on Saturday or Sunday?
-P 2/7

19.
What is the probability of winning a raffle if 500 tickets are sold and you buy 5 of them?
P 5/500

20.
A class of 25 students has 15 girls and 10 boys. If one student is chosen at random, what is the probability it is a girl?
P 15/20

21.
There are 26 letters in the alphabet(no, really?). What is the probability that a letter chosen at random is in the word MATHEMATICS?
P 8/26

Page E-50

4. Solve.

(N) If you flip a coin 150 times, about how many times would you expect to get heads?

You should get 75 times of getting a head... or 1/2 because there is a 50% of chance that you can get a head and another 50% of getting a tail if you flip the coin once. So flipping the coin 150 times will give you an expectation of 75 because 50% of 150 of 75.

(C) The letters a, e, i, o, u, and y are vowels. If one letter of the alphabet is chosen at random, what is the probability it is a vowel?

The answer should be 6/26 or if you simplify it (by the number 2), you should get 3/13 because the alphabet has 26 letters in total and the vowels would be 6 letters out of 26. Also Mr. Harbeck has taught us an easy way of figuring what the answer would be for questions like this.
---------------------------------------
vowels
-----------------
total letters of alphabet
---------------------------------------
6____ 3
----- = -----
26 ___13
---------------------------------------
(K) If you randomly pick a date in April, how many equally likely outcomes are there?

Usually each months should have only 30 or 31 days unless it's February then you have 28 days and if it's a leap year then you get 29 days in February. But we only need to solve for the month of April and the equally likely outcomes should be 30 because April only has 30 days so the number of 30 days is most likely to be the outcomes of April. So if you pick a ramdomly date in April, you should be picking a date between April 1st and April 30th. I have also checked the calendars of the year 2004 and 2005 to make sure that April has only 30 days.

(P) A magician asks you to pick a card, any card, from a standard deck of 52 cards. What is the probability of picking an Ace?

The answer should be a 4 because every number has 4 cards each, a card of hearts, clubs, spades and diamonds. Also, there are 13 numbers (and letters) in a deck. A number 2, 3, 4, 5, 6, 7, 8, 9, and letters such as an Ace, Jack, Queen and a King. So there are 52 cards in a deck, and each number contains 4 cards each, so the probability of getting an Ace is 4/52 or if you simplify it by the number 4, you will get 1/13.
---------------------------------------
number of Aces in deck
-------------------------
number of cards in deck
----------------------------------------------
4______ 1
------- = -------
26 _____13
My own question:
The prize of \$500 dollars is only won by winning the 1st bingo game. The other 5 winners will win \$20 dollars. If you were playing bingo with the other 299 people and each person only has 1 bingo card, what is the probability of winning \$500 ? What is the probability of winning \$20? What is the probability of winning \$500 and \$20?
P.S. Hints are given =)
K.V. 8-41 (October 16, 2006)

I. Find each probability if you spin the spinner once. (questions 1-6)

1. P(red)
1/5

2. P(green)
1/5

3. P(blue or white)
2/5

4.P(not yellow)
4/5

5. P(not red)
4/5

6. P (blue or red or yellow)
3/5

P.S. I can't scan because my scanner doesn't work right now and for some reason I can't upload any pictures either so that's why I don't have a picture on this post.

picture is up

### Question 2 on E-49

Find each probability if you choose one card at random.

7. P(striped) = 3/8 = 37.5 %

8. P(white) = 4/8 = 1/2 = 50%

9. P(shaded) = 1/8 = 12.5%

10. P(white or shaded) = 5/8 = 62.5

11. P(striped or white) = 7/8 = 87.5

12.
P
(striped or shaded) = 4/8 = 1/2 = 50%

13. P(not striped) = 5/8 = 62.5%

14. P(not white) = 4/8 = 1/2 = 50%

15. P(striped or white or shaded) = 1 whole = 100%

If we were to add four more cards to the deck. What will the possibility of drawing a striped, white or shaded at random?

16. P(striped)

17. P(white)

18.

19.

20.
P(striped or white)

21.

22.
P(not striped)

23.
P(not white)

24.

## Thursday, October 05, 2006

### Making a Personal Learning Network

I would like you to create a Personal Learning Network. This is a network of Blogs and other sites that have RSS feeds. You could start with the 5 blogs out of Sargent Park and branch off from there.

Here is a 7 minute screencast that shows you how to set up a Bloglines Account. After you watch it please start to make your own Personal Learning Network. This is the second attempt at making it loud enough. Can you hear me now:-)

How to make a Personal Learning Network.

You need to create a Bloglines Account. Bloglines is a service that collects all the new posts from blogs that you subscribe too.

In your email respond to the bloglines email by clicking on the link.
I would suggest skipping the next page and clicking on

Now for the good stuff!!

T
o start your Personal Learning Network I would like you to subscribe to the 4 math classes and the Sargent Park Math Hub. This will keep you up to date when other students create posts that you would like to view and comment on. Commenting on each others work is the most important aspect of blogging.

In the window
paste the following url
www.sargentparkmathzone.blogspot.com

Use the following feed to subscribe (click the box in the right corner).
Choose new folder
save as
now click subscribe.

You now have a new screen. This is your dashboard for Bloglines. To add the remaining blogs
816math.blogspot.com
817math.blogspot.com
841math.blogspot.com
873math.blogspot.com

Click add in the upper left hand corner.

Paste the address in the subscribe box then make sure you put this new blog in the following folder
Click subscribe and do the rest of the class sites.

These 5 blogs will be the start to your Personal Learning network. Next stop other sites that will help with your personal learning.

But that is another post!!!

## Sunday, October 01, 2006

### Why we learn Math

As I was cruising the net looking for something interesting to say I found this movie at Google Movies. The Math Lesson

is the reason why we learn math and need to understand the concepts behind the arithmatic.

Enjoy the show!!